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MHT CET 2026 (19 Apr, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2026 (19 Apr, Shift 1)

Q2MHT CET 2026 · 19 APR · SHIFT 1Easy

Thermometry & Thermal Expansion

If the two temperatures on Fahrenheit scale differ by 54∘54^\circF, then the difference in temperature on the Celsius scale is

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Answer: (a)

  1. 100100 C divisions =180=180 F divisions, so ΔC=59ΔF\Delta C=\frac{5}{9}\Delta F.
  2. ΔC=59×54=30\Delta C=\frac{5}{9}\times 54=30
  3. So the answer is (a) 30∘30^\circC.
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