If the velocity of a body related to displacement x is given by v = √(5000 + 24x) m/s, then the acceleration of the body is.................... m/s2. Numerical answer type. Work it out, then open the answer.

Answer: 12. v² = 5000 + 24x a = 1/2(d(v²))/(dx) = 24/2 So a = 12 m/s².

If the velocity of a body related to displacement x is given by v =… | JEE Main 2021 (27 Aug, Shift 1)

Q27JEE Main 2021 · 27 AUG · SHIFT 1Medium

Velocity, Acceleration & Variable Motion

If the velocity of a body related to displacement x is given by $v = \sqrt{5000 + 24x}$ m/s, then the acceleration of the body is .................... m/s2.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 12

$v^2 = 5000 + 24x$
$a = \dfrac{1}{2}\dfrac{d(v^2)}{dx} = \dfrac{24}{2}$
So $a = 12\text{ m/s}^2$ .

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