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NEET 2016 (Phase 1) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from NEET 2016 (Phase 1)

Q33NEET 2016 · PHASE 1Easy

Velocity, Acceleration & Variable Motion

If the velocity of a particle is v = At + Bt2, where A and B are constants, then the distance travelled by it between 1 s and 2 s is

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Answer: (a)

  1. v>0v > 0 for tt between 1 s and 2 s (A, B positive), so distance =∫12v dt= \int_1^2 v\,dt
  2. ∫12(At+Bt2) dt=A2(4−1)+B3(8−1)\int_1^2 (At + Bt^2)\,dt = \dfrac{A}{2}(4 - 1) + \dfrac{B}{3}(8 - 1)
  3. =32A+73B= \dfrac{3}{2}A + \dfrac{7}{3}B
  4. So the answer is (a).
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