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JEE Main 2021 (20 Jul, Shift 2) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2021 (20 Jul, Shift 2)

Q44JEE Main 2021 · 20 JUL · SHIFT 2Easy

Applications of Dimensional Analysis

If time (t), velocity (v), and angular momentum (l) are taken as the fundamental units. Then the dimension of mass (m) in terms of t, v and l is:

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Answer: (d)

Angular momentum $l = mvr$ and $r = vt$ , so $l = m v^2 t$ .
$m = \dfrac{l}{v^2 t}$ .
$[m] = [t^{-1}v^{-2}l^{1}]$ , so the answer is (d).

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