Physics Circle home Student Login

Home›Chapters›Electrostatics PYQs›Electric Charge & Coulomb's Law›Question 40

JEE Main 2023 (24 Jan, Shift 1) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from JEE Main 2023 (24 Jan, Shift 1)

Q40JEE Main 2023 · 24 JAN · SHIFT 1Easy

Electric Charge & Coulomb's Law

If two charges q1{}_1 and q2{}_2 are separated with distance 'd' and placed in a medium of dielectric constant K. What will be the equivalent distance between charges in air for the same electrostatic force?

Show answer and solution

Answer: (a)

  1. In medium F=kq1q2Kd2F = \dfrac{kq_1q_2}{K d^2}; in air F=kq1q2d′2F = \dfrac{kq_1q_2}{d'^2}.
  2. d′=dKd' = d\sqrt{K}
  3. So the answer is (a) dKd\sqrt{K}.
Report a mistake

More questions on Electric Charge & Coulomb's Law