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MHT CET 2026 (13 Apr, Shift 2) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from MHT CET 2026 (13 Apr, Shift 2)

Q5MHT CET 2026 · 13 APR · SHIFT 2Easy

Electric Charge & Coulomb's Law

If two charges $q_1$ and $q_2$ are separated with distance 'd' and placed in a medium of dielectric constant $K$ . What will be the equivalent distance between charges in air for the same electrostatic force?

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Answer: (a)

In medium $F = \dfrac{kq_1q_2}{K d^2}$ ; in air at distance $d'$ : $F = \dfrac{kq_1q_2}{d'^2}$ .
$d'^2 = K d^2 \Rightarrow d' = d\sqrt{K}$
So the answer is (a) $d[K]^{1/2}$ .

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