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MHT CET 2023 (13 May, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2023 (13 May, Shift 2)

Q44MHT CET 2023 · 13 MAY · SHIFT 2Easy

Acceleration Due to Gravity

If two planets have their radii in the ratio x:yx : y and densities in the ratio m:nm : n, then the acceleration due to gravity on them are in the ratio

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Answer: (d)

  1. g=43πGρRg = \frac{4}{3}\pi G\rho R, so g∝ρRg \propto \rho R.
  2. g1g2=mn⋅xy=mxny\frac{g_1}{g_2} = \frac{m}{n}\cdot\frac{x}{y} = \frac{mx}{ny}
  3. So the answer is (d).
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