If two resistors of resistances have values R₁ = (350 ± 3) Ω and R₂ = (140 ± 4) Ω. The percentage error for the sum and difference of R₁ and R₂ are respectively (a) 1.43%, 3.33% (b) 7%, 1% (c) 1%, 7% (d) 3.33%, 1.43%

Answer: (a). In sum and difference, absolute errors add: Δ = 3 + 4 = 7 Ω Sum = 490 Ω: 7/490 × 100 = 1.43% Difference = 210 Ω: 7/210 × 100 = 3.33% So the answer is (a).

If two resistors of resistances have values R₁ = (350 ± 3) Ω and R₂ =… | MHT CET 2026 (18 Apr, Shift 1)

Q2MHT CET 2026 · 18 APR · SHIFT 1Easy

Errors in Measurement

If two resistors of resistances have values $R_1 = (350 \pm 3)\ \Omega$ and $R_2 = (140 \pm 4)\ \Omega$ . The percentage error for the sum and difference of $R_1$ and $R_2$ are respectively

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Answer: (a)

In sum and difference, absolute errors add: $\Delta = 3 + 4 = 7\ \Omega$
Sum $= 490\ \Omega$ : $\frac{7}{490} \times 100 = 1.43\%$
Difference $= 210\ \Omega$ : $\frac{7}{210} \times 100 = 3.33\%$
So the answer is (a).

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