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JEE Main 2021 (31 Aug, Shift 2) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2021 (31 Aug, Shift 2)

Q42JEE Main 2021 · 31 AUG · SHIFT 2Easy

Applications of Dimensional Analysis

If velocity [V], time [T] and force [F] are chosen as the base quantities, the dimensions of the mass will be:

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Answer: (b)

  1. From F=ma=mVTF = ma = m\dfrac{V}{T}, mass is m=FTVm = \dfrac{FT}{V}.
  2. So [m]=[F T V−1][m] = [F\,T\,V^{-1}].
  3. So the answer is (b) [FTV−1][FTV^{-1}].
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