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MHT CET 2026 (20 Apr, Shift 2) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from MHT CET 2026 (20 Apr, Shift 2)

Q4MHT CET 2026 · 20 APR · SHIFT 2Easy

Angle of Contact & Capillarity

If we dip capillary tubes of different radii rnr_n in water and the water rises to different heights hnh_n in them, then (n=1,2,3n = 1, 2, 3 .........)

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Answer: (d)

  1. h=2Tcos⁡θrρgh = \frac{2T\cos\theta}{r\rho g}, so for the same liquid and tube material hr=2Tcos⁡θρghr = \frac{2T\cos\theta}{\rho g} = constant.
  2. So the answer is (d) hnrnh_n r_n = constant.
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