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JEE Main 2026 (2 Apr, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2026 (2 Apr, Shift 2)

Q28JEE Main 2026 · 2 APR · SHIFT 2Medium

Logic Gates

If X and Y are the inputs, the given circuit works as _________.

Figure

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Answer: (d)

  1. Tied NANDs act as NOT: Xˉ\bar X, Yˉ\bar Y.
  2. Middle NAND: XˉYˉ‾=X+Y\overline{\bar X \bar Y} = X + Y.
  3. Last tied NAND (NOT): output =X+Y‾= \overline{X+Y}.
  4. So the answer is (d) NOR gate.
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