Velocity & Acceleration in SHM question from MHT CET 2019 (2 May, Shift 2)

Answer: (a)

1. In SHM $a = -\omega^2 x = -\frac{4\pi^2}{T^2}x$.
2. $\frac{aT}{x} = -\frac{4\pi^2}{T}$, a constant.
3. The other expressions contain $a$, $v$ or $t$ in combinations that vary with time.
4. So the answer is (a) $\frac{aT}{x}$.