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MHT CET 2021 (21 Sep, Shift 2) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from MHT CET 2021 (21 Sep, Shift 2)

Q48MHT CET 2021 · 21 SEP · SHIFT 2Easy

Angle of Contact & Capillarity

In a capillary tube having area of cross-section A, water rises to a height 'h'. If cross-sectional area is reduced to A9\frac{A}{9}, the rise of water in the capillary tube is

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Answer: (a)

  1. h∝1r∝1Ah \propto \frac{1}{r} \propto \frac{1}{\sqrt{A}}
  2. A′=A9⇒r′=r3⇒h′=3hA' = \frac{A}{9} \Rightarrow r' = \frac{r}{3} \Rightarrow h' = 3h
  3. So the answer is (a) 3h3h.
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