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MHT CET 2021 (23 Sep, Shift 2) · Junction Transistor

Junction Transistor question from MHT CET 2021 (23 Sep, Shift 2)

Q69MHT CET 2021 · 23 SEP · SHIFT 2Medium

Junction Transistor

In a CE transistor, a change of 8.0 mA8.0\text{ mA} in the emitter current produces a change of 7.8 mA7.8\text{ mA} in the collector current. What change in the base current is necessary to produce the same change in the collector current?

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Answer: (a)

  1. IE=IB+IC⇒ΔIB=ΔIE−ΔICI_E = I_B + I_C \Rightarrow \Delta I_B = \Delta I_E - \Delta I_C
  2. ΔIB=8.0−7.8=0.2\Delta I_B = 8.0 - 7.8 = 0.2 mA =200 μ= 200\ \muA.
  3. So the answer is (a) 200 μ200\ \muA.
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