In a coil, the current changes from -2 A to +2 A in 0.2 s and induces an emf of 0.1 V. The self inductance of the coil is: (a) 4 mH (b) 2.5 mH (c) 1 mH (d) 5 mH

Answer: (d). e = L (Δ I)/(Δ t) ⇒ L = (e Δ t)/(Δ I) Δ I = 2-(-2) = 4 A L = (0.1×0.2)/(4) = 5×10⁻³ H So the answer is (d) 5 mH.

In a coil, the current changes from -2 A to +2 A in 0.2 s and induces… | JEE Main 2024 (6 Apr, Shift 2)

Q37JEE Main 2024 · 6 APR · SHIFT 2Easy

Self-Inductance & Energy

In a coil, the current changes from $-2\text{ A}$ to $+2\text{ A}$ in $0.2\text{ s}$ and induces an emf of $0.1\text{ V}$ . The self inductance of the coil is:

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Answer: (d)

$e = L\,\dfrac{\Delta I}{\Delta t} \Rightarrow L = \dfrac{e\,\Delta t}{\Delta I}$
$\Delta I = 2-(-2) = 4\text{ A}$
$L = \dfrac{0.1\times0.2}{4} = 5\times10^{-3}\text{ H}$
So the answer is (d) 5 mH.

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