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JEE Main 2006 (AIEEE) · Junction Transistor

Junction Transistor question from JEE Main 2006 (AIEEE)

Q116JEE Main 2006 · AIEEEEasy

Junction Transistor

In a common base mode of a transistor, the collector current is $5.488\,mA$ for an emitter current of $5.60\,mA.$ The value of the base current amplification factor $(\beta)$ will be

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Answer: (a)

$I_B = I_E - I_C = 5.60 - 5.488 = 0.112$ mA
$\beta = \frac{I_C}{I_B} = \frac{5.488}{0.112} = 49$
So the answer is (a) 49.

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