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Junction Transistor question from JEE Main 2017

Q92JEE Main 2017Easy

Junction Transistor

In a common emitter amplifier circuit using an n-p-n transistor, the phase difference between the input and the output voltages will be:

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Answer: (a)

In CE mode, $V_o = V_{CC} - I_C R_L$ : when input rises, $I_C$ rises and $V_o$ falls.
So output is inverted, phase difference $180^\circ$ .
So the answer is (a) $180^\circ$ .

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