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Junction Transistor question from NEET 2013

Q104NEET 2013Difficult

Junction Transistor

In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will be

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Answer: (c)

  1. Voltage gain Av=gmRLA_v = g_m R_L; it depends only on transconductance for the same load.
  2. G′G=0.020.03=23\dfrac{G'}{G} = \dfrac{0.02}{0.03} = \dfrac{2}{3}
  3. So the answer is (c) 23G\dfrac{2}{3}G.
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