In a common emitter transistor amplifier, AC current gain is 65, the load resistance is 5400 Ω and input resistance of the transistor is 450 Ω. The voltage gain is (a) 460 (b) 540 (c) 780 (d) 7800

Answer: (c). AV = β(RL)/(ri) AV = 65 × (5400)/(450) = 65 × 12 = 780 So the answer is (c) 780.

In a common emitter transistor amplifier, AC current gain is 65, the… | MHT CET 2026 (20 Apr, Shift 1)

Q9MHT CET 2026 · 20 APR · SHIFT 1Easy

Junction Transistor

In a common emitter transistor amplifier, AC current gain is $65$ , the load resistance is $5400\,\Omega$ and input resistance of the transistor is $450\,\Omega$ . The voltage gain is

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Answer: (c)

$A_V = \beta\frac{R_L}{r_i}$
$A_V = 65 \times \frac{5400}{450} = 65 \times 12 = 780$
So the answer is (c) 780.

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