In a common emitter transistor amplifier circuit, the input resistance is 1.8 kΩ and output is obtained across a load resistance of 9 kΩ. The alternating current gain is 70. Corresponding to an a.c. input voltage of 6 mV, the output voltage will be (a) 0.7 V (b) 1.4 V (c) 2.1 V (d) 4.2 V

Answer: (c). AV = β (RL)/(Ri) = 70 × 9/1.8 = 350 Vo = AV Vi = 350 × 6 × 10⁻³ = 2.1 V So the answer is (c) 2.1 V.

In a common emitter transistor amplifier circuit, the input… | MHT CET 2025 (26 Apr, Shift 1)

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Junction Transistor

In a common emitter transistor amplifier circuit, the input resistance is $1.8\text{ k}\Omega$ and output is obtained across a load resistance of $9\text{ k}\Omega$ . The alternating current gain is 70. Corresponding to an a.c. input voltage of 6 mV, the output voltage will be

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Answer: (c)

$A_V = \beta \dfrac{R_L}{R_i} = 70 \times \dfrac{9}{1.8} = 350$
$V_o = A_V V_i = 350 \times 6 \times 10^{-3} = 2.1$ V
So the answer is (c) 2.1 V.

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