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MHT CET 2026 (19 May, Shift 1) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from MHT CET 2026 (19 May, Shift 1)

Q19MHT CET 2026 · 19 MAY · SHIFT 1Medium

Resonance, Bandwidth & Q Factor

In a discharging series L-C-R circuit, C=2 μC = 2\ \muF, L=1L = 1 mH and R=10 ΩR = 10\ \Omega. The ratio of the energies stored in the inductor and in the capacitor, when the maximum current flows in the circuit, is

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Answer: (d)

  1. Current is maximum when dIdt=0\frac{dI}{dt} = 0, so VL=0V_L = 0 and VC=IRV_C = IR (loop rule).
  2. UL=12LI2U_L = \frac{1}{2}LI^2, UC=12CVC2=12CI2R2U_C = \frac{1}{2}CV_C^2 = \frac{1}{2}CI^2R^2
  3. ULUC=LCR2=10−32×10−6×100=5\frac{U_L}{U_C} = \frac{L}{CR^2} = \frac{10^{-3}}{2\times10^{-6}\times100} = 5
  4. So the answer is (d) 5:15 : 1.
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