Physics Circle home Student Login

Home›Chapters›Wave Optics PYQs›YDSE: Film, Medium & Two Wavelengths›Question 58

JEE Main 2019 (12 Apr, Shift 1) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from JEE Main 2019 (12 Apr, Shift 1)

Q58JEE Main 2019 · 12 APR · SHIFT 1Medium

YDSE: Film, Medium & Two Wavelengths

In a double slit experiment, when a thin film of thickness t having refractive index μ\mu. is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t is (λ\lambda is the wavelength of the light used):

Show answer and solution

Answer: (d)

  1. Film adds path (μ−1)t(\mu - 1)t; a shift of one fringe means this equals λ\lambda.
  2. (μ−1)t=λ⇒t=λμ−1(\mu - 1)t = \lambda \Rightarrow t = \dfrac{\lambda}{\mu - 1}
  3. So the answer is (d) λ(μ−1)\frac{\lambda}{(\mu - 1)}.
Report a mistake

More questions on YDSE: Film, Medium & Two Wavelengths