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NEET 1995 (AIPMT) · Biprism, Thin Films & Other Devices

Biprism, Thin Films & Other Devices question from NEET 1995 (AIPMT)

Q30NEET 1995 · AIPMTMedium

Biprism, Thin Films & Other Devices

In a Fresnel biprism experiment, the two positions of lens give separation between the slits as 16 cm and 9 cm respectively. What is the actual distance of separation?

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Answer: (d)

Displacement method: actual separation $d = \sqrt{d_1 d_2}$ .
$d = \sqrt{16 \times 9} = 12\ \text{cm}$ .
So the answer is (d) 12 cm.

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