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MHT CET 2025 (19 Apr, Shift 2) · Logic Gates

Logic Gates question from MHT CET 2025 (19 Apr, Shift 2)

Q42MHT CET 2025 · 19 APR · SHIFT 2Medium

Logic Gates

In a given logic circuit, the output Y when all the three inputs A,B,C\mathrm{A}, \mathrm{B}, \mathrm{C} are first low and then high will be respectively

Figure

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Answer: (c)

  1. Y=Aˉ+B⋅C‾Y = \bar{A} + \overline{B \cdot C} (NOT on A, NAND on B, C, then OR).
  2. All low: Y=1+0‾=1Y = 1 + \overline{0} = 1.
  3. All high: Y=0+1‾=0Y = 0 + \overline{1} = 0.
  4. So the answer is (c) (1,0)(1, 0).
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