In a gravitational field, the gravitational potential is given by, V = -K/x (J/Kg). The gravitational field intensity at point (2, 0, 3) m is (a) +K/4 (b) +K/2 (c) -K/2 (d) -K/4

Answer: (d). Field E = -dV/dx. E = -d/dx(-K/x) = -K/x² Only x matters; at (2,0,3), x = 2: E = -K/4 So the answer is (d) -K/4.

In a gravitational field, the gravitational potential is given by, V… | NEET 2022 (Phase 2)

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Gravitational Field

In a gravitational field, the gravitational potential is given by, $V = -\frac{K}{x}$ (J/Kg). The gravitational field intensity at point (2, 0, 3) m is

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Answer: (d)

Field $E = -\frac{dV}{dx}$ .
$E = -\frac{d}{dx}\left(-\frac{K}{x}\right) = -\frac{K}{x^2}$
Only $x$ matters; at $(2,0,3)$ , $x = 2$ : $E = -\frac{K}{4}$
So the answer is (d) $-\frac{K}{4}$ .

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