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JEE Main 2025 (29 Jan, Shift 1) · Density, Compressibility & Pascal's Law

Density, Compressibility & Pascal's Law question from JEE Main 2025 (29 Jan, Shift 1)

Q7JEE Main 2025 · 29 JAN · SHIFT 1Easy

Density, Compressibility & Pascal's Law

In a hydraulic lift, the surface area of the input piston is 6 cm2 and that of the output piston is 1500 cm2. If 100 N force is applied to the input piston to raise the output piston by 20 cm, then the work done is _______ kJ.

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. Output force: F2=F1A2A1=100×15006=25000 NF_2 = F_1\dfrac{A_2}{A_1} = 100\times\dfrac{1500}{6} = 25000\text{ N}.
  2. Work done on the load: W=F2d=25000×0.20=5000 JW = F_2 d = 25000\times0.20 = 5000\text{ J}
  3. So the work done is 5 kJ.
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