In a hydraulic press, the piston in the small cylinder has a diameter of d₁ cm, while the larger piston has a diameter of d₂ cm. If a force F₁ is applied to the small piston, then the force F₂ on the large piston is given by (a) F₂ = (d₂²)/(d₁²) F₁ (b) F₂ = (d₁²)/(d₂²) F₁ (c) F₂ = (d₂²)/(d₁²) 1/F₁ (d) F₂ = (d₁²)/(d₂²) 1/F₁

Answer: (a). Pascal's law: same pressure on both pistons, (F₁)/(A₁) = (F₂)/(A₂). A ∝ d², so F₂ = (d₂²)/(d₁²)F₁. So the answer is (a).

In a hydraulic press, the piston in the small cylinder has a diameter… | MHT CET 2026 (19 May, Shift 2)

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Density, Compressibility & Pascal's Law

In a hydraulic press, the piston in the small cylinder has a diameter of $d_1$ cm, while the larger piston has a diameter of $d_2$ cm. If a force $F_1$ is applied to the small piston, then the force $F_2$ on the large piston is given by

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Answer: (a)

Pascal's law: same pressure on both pistons, $\dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}$ .
$A \propto d^2$ , so $F_2 = \dfrac{d_2^2}{d_1^2}F_1$ .
So the answer is (a).

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Density, Compressibility & Pascal's Law question from MHT CET 2026 (19 May, Shift 2)

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