In a hydraulic press, the small cylinder has a diameter of d₁ cm, while the large cylinder has a diameter of d₂ cm. If a force F₁ is applied to a piston of small cylinder, then the force on the piston of large cylinder F₂ is (a) (d₁²)/(d₂²) 1/F₁ (b) (d₁²)/(d₂²) F₁ (c) (d₂²)/(d₁²) 1/F₁ (d) (d₂²)/(d₁²) F₁

Answer: (d). Pascal's law: (F₁)/(A₁) = (F₂)/(A₂) with A ∝ d². F₂ = (d₂²)/(d₁²)F₁ So the answer is (d).

In a hydraulic press, the small cylinder has a diameter of d₁ cm… | MHT CET 2026 (12 May, Shift 1)

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Density, Compressibility & Pascal's Law

In a hydraulic press, the small cylinder has a diameter of $d_1$ cm, while the large cylinder has a diameter of $d_2$ cm. If a force $F_1$ is applied to a piston of small cylinder, then the force on the piston of large cylinder $F_2$ is

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Answer: (d)

Pascal's law: $\dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}$ with $A \propto d^2$ .
$F_2 = \dfrac{d_2^2}{d_1^2}F_1$
So the answer is (d).

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Density, Compressibility & Pascal's Law question from MHT CET 2026 (12 May, Shift 1)

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