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JEE Main 2020 (2 Sep, Shift 2) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2020 (2 Sep, Shift 2)

Q52JEE Main 2020 · 2 SEP · SHIFT 2Difficult

Transitions, Photon Emission & Excitation

In a hydrogen atom the electron makes a transition from (n + 1)th level to the nth level. If n >> 1, the frequency of radiation emitted is proportional to:

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Answer: (c)

$\nu \propto \frac{1}{n^2} - \frac{1}{(n+1)^2} = \frac{2n+1}{n^2(n+1)^2}$
For $n \gg 1$ : $\nu \propto \frac{2n}{n^4} = \frac{2}{n^3}$
So the answer is (c) $\frac{1}{n^3}$ .

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