In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of emitted radiation is λ. If an electron jumps from N-shell to the L-shell, the wavelength of emitted radiation will be: (a) 25/16λ (b) 27/20λ (c) 16/25λ (d) 20/27λ

Answer: (d). K, L, M, N shells are n = 1, 2, 3, 4. M to L: (1)/(λ) ∝ 1/4 - 1/9 = 5/36 N to L: (1)/(λ') ∝ 1/4 - 1/16 = 3/16 λ' = λ × (5/36)/(3/16) = 20/27λ, so the answer is (d).

In a hydrogen like atom, when an electron jumps from the M-shell to… | JEE Main 2019 (11 Jan, Shift 2)

Q55JEE Main 2019 · 11 JAN · SHIFT 2Medium

Transitions, Photon Emission & Excitation

In a hydrogen like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of emitted radiation is $\lambda$ . If an electron jumps from N-shell to the L-shell, the wavelength of emitted radiation will be:

Show answer and solution

Answer: (d)

K, L, M, N shells are $n = 1, 2, 3, 4$ .
M to L: $\frac{1}{\lambda} \propto \frac{1}{4} - \frac{1}{9} = \frac{5}{36}$
N to L: $\frac{1}{\lambda'} \propto \frac{1}{4} - \frac{1}{16} = \frac{3}{16}$
$\lambda' = \lambda \times \frac{5/36}{3/16} = \frac{20}{27}\lambda$ , so the answer is (d).

Report a mistake

Transitions, Photon Emission & Excitation question from JEE Main 2019 (11 Jan, Shift 2)

More questions on Transitions, Photon Emission & Excitation