In a hypothetical fission reaction ₉₂X²³⁶ → ₅₆Y¹⁴¹ + ₃₆Z⁹² + 3R The identity of emitted particles (R) is: (a) Proton (b) Neutron (c) Electron (d) γ -radiations

Answer: (b). A: 236 = 141 + 92 + 3AR ⇒ AR = 1 Z: 92 = 56 + 36 + 3ZR ⇒ ZR = 0 A particle with A = 1, Z = 0 is a neutron. So the answer is (b) Neutron.

In a hypothetical fission reaction ₉₂X²³⁶ → ₅₆Y¹⁴¹ + ₃₆Z⁹² + 3R The… | JEE Main 2024 (8 Apr, Shift 2)

Q6JEE Main 2024 · 8 APR · SHIFT 2Easy

Nuclear Fission & Fusion

In a hypothetical fission reaction

${}_{92}X^{236} \rightarrow {}_{56}\text{Y}^{141} + {}_{36}Z^{92} + 3R$

The identity of emitted particles (R) is:

Show answer and solution

Answer: (b)

Which of the following nuclear fragments corresponding to nuclear fission between neutron…JEE Main 2024 (4 Apr, Shift 1)
Water is used as a coolant in a nuclear reactor because of itsNEET 2024
The disintegration energy Q for the nuclear fission of ²³⁵U → ¹⁴⁰Ce + ⁹⁴Zr + n is _______…JEE Main 2024 (4 Apr, Shift 2)
In a nuclear fission process, a high mass nuclide (A ≈ 236) with binding energy 7.6 MeV/…JEE Main 2024 (27 Jan, Shift 1)
The explosive in a Hydrogen bomb is a mixture of ₁H², ₁H³ and ₃Li⁶ in some condensed…JEE Main 2024 (29 Jan, Shift 1)
If three helium nuclei combine to form a carbon nucleus then the energy released in this…JEE Main 2024 (5 Apr, Shift 1)
In a nuclear fission reaction of an isotope of mass M, three similar daughter nuclei of…JEE Main 2024 (30 Jan, Shift 2)
The energy released in the fusion of 2 kg of hydrogen deep in the sun is EH and the…JEE Main 2024 (9 Apr, Shift 2)