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MHT CET 2022 (11 Aug, Shift 2) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from MHT CET 2022 (11 Aug, Shift 2)

Q44MHT CET 2022 · 11 AUG · SHIFT 2Medium

Periodic Motion & SHM Basics

In a medium, the phase difference between two particles separated by a distance 'xx' is (π5)\left(\frac{\pi}{5}\right)c. If the frequency of the oscillation of particles is 25 Hz25\text{ Hz} and the velocity of propagation of the waves is 75 m/s75\text{ m/s}, then the value of xx is

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Answer: (d)

  1. λ=vf=7525=3 m\lambda = \frac{v}{f} = \frac{75}{25} = 3\text{ m}
  2. x=λ2πΔϕ=32π⋅π5=0.3 mx = \frac{\lambda}{2\pi}\Delta\phi = \frac{3}{2\pi}\cdot\frac{\pi}{5} = 0.3\text{ m}
  3. So the answer is (d) 0.3 m.
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