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JEE Main 2004 (AIEEE) · Wheatstone Bridge & Metre Bridge

Wheatstone Bridge & Metre Bridge question from JEE Main 2004 (AIEEE)

Q84JEE Main 2004 · AIEEEEasy

Wheatstone Bridge & Metre Bridge

In a meter bridge experiment null point is obtained at 20 cm20\text{ cm}, from one end of the wire when resistance XX is balanced against another resistance Y.Y. If X<YX < Y, then where will be the new position of the null point from the same end, if one decides to balance a resistance of 4X4X against YY

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Answer: (c)

  1. Initially XY=2080=14\dfrac{X}{Y} = \dfrac{20}{80} = \dfrac{1}{4}
  2. Now 4XY=1=l100−l\dfrac{4X}{Y} = 1 = \dfrac{l}{100-l}
  3. l=100−l⇒l=50l = 100 - l \Rightarrow l = 50 cm
  4. So the answer is (c) 50 cm50\text{ cm}.
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