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JEE Main 2017 (9 Apr, Shift 1) · Wheatstone Bridge & Metre Bridge

Wheatstone Bridge & Metre Bridge question from JEE Main 2017 (9 Apr, Shift 1)

Q76JEE Main 2017 · 9 APR · SHIFT 1Medium

Wheatstone Bridge & Metre Bridge

In a meter bridge experiment resistances are connected as shown in the figure. Initially resistance P = 4 Ω\Omega and the neutral point N is at 60 cm from A. Now an unknown resistance R is connected in series to P and the new position of the neutral point is at 80 cm from A. The value of unknown resistance R is:

Figure

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Answer: (d)

  1. PQ=6040⇒Q=83 Ω\dfrac{P}{Q} = \dfrac{60}{40} \Rightarrow Q = \dfrac{8}{3}\ \Omega.
  2. 4+RQ=8020=4⇒4+R=323\dfrac{4+R}{Q} = \dfrac{80}{20} = 4 \Rightarrow 4 + R = \dfrac{32}{3}.
  3. R=203 ΩR = \dfrac{20}{3}\ \Omega. So the answer is (d).
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