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JEE Main 2026 (21 Jan, Shift 1) · Optical Instruments & the Eye

Optical Instruments & the Eye question from JEE Main 2026 (21 Jan, Shift 1)

Q6JEE Main 2026 · 21 JAN · SHIFT 1Medium

Optical Instruments & the Eye

In a microscope the objective is having focal length fo=2 cmf_o = 2\text{ cm} and eye-piece is having focal length fe=4 cmf_e = 4\text{ cm}. The tube length is 32 cm. The magnification produced by this microscope for normal adjustment is ______.

Numerical answer type. Work it out, then open the answer.

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Answer: 100

  1. Normal adjustment: M=Lfo⋅DfeM = \dfrac{L}{f_o} \cdot \dfrac{D}{f_e}.
  2. M=322×254=16×6.25M = \dfrac{32}{2} \times \dfrac{25}{4} = 16 \times 6.25.
  3. Magnification =100= 100.
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