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JEE Main 2020 (4 Sep, Shift 2) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from JEE Main 2020 (4 Sep, Shift 2)

Q58JEE Main 2020 · 4 SEP · SHIFT 2Medium

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased:

Figure

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Answer: (b)

  1. eV=hcλ−ϕeV = \frac{hc}{\lambda} - \phi: slope hc/ehc/e and intercept depend only on constants and the metal.
  2. Intensity changes only the number of photoelectrons (current), not VV.
  3. So the answer is (b) the graph does not change.
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