In a photoelectric experiment, a graph of maximum kinetic energy (KE max) against the frequency of incident radiation (v) is plotted. If A and B are the intercepts on the X and Y axis respectively then the Planck's constant is given by (a) A + B (b) B/A (c) A × B (d) A/B

Answer: (b). A-BKEνslope = h KEmax = hν - φ. X-intercept ( KE = 0): A = ν₀ = φ/h. Y-intercept magnitude: B = φ. Slope h = (φ)/(ν₀) = B/A. So the answer is (b) B/A.

In a photoelectric experiment, a graph of maximum kinetic energy (KE… | MHT CET 2021 (24 Sep, Shift 2)

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs

In a photoelectric experiment, a graph of maximum kinetic energy $(\mathrm{KE}$ max $)$ against the frequency of incident radiation (v) is plotted. If $\mathrm{A}$ and $\mathrm{B}$ are the intercepts on the $\mathrm{X}$ and $\mathrm{Y}$ axis respectively then the Planck's constant is given by

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Answer: (b)

$KE_{max} = h\nu - \phi$ .
X-intercept ( $KE = 0$ ): $A = \nu_0 = \phi/h$ . Y-intercept magnitude: $B = \phi$ .
Slope $h = \frac{\phi}{\nu_0} = \frac{B}{A}$ .
So the answer is (b) $\frac{B}{A}$ .

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2021 (24 Sep, Shift 2)

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