In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2.0× 10¹⁰ Hz and amplitude 48 V m⁻¹. Then the amplitude of oscillating magnetic field is: (Speed of light in free space = 3× 10⁸ m s⁻¹) (a) 1.6× 10⁻⁸ T (b) 1.6× 10⁻⁷ T (c) 1.6× 10⁻⁶ T (d) 1.6× 10⁻⁹ T

Answer: (b). B₀ = E₀/c; the frequency is not needed. B₀ = 483× 10⁸ = 1.6× 10⁻⁷ T. So the answer is (b).

In a plane electromagnetic wave travelling in free space, the… | NEET 2023

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Nature of EM Waves & Wave Equation

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0\times 10^{10}\text{ Hz}$ and amplitude $48\text{ V m}^{-1}$ . Then the amplitude of oscillating magnetic field is: (Speed of light in free space $= 3\times 10^{8}\text{ m s}^{-1}$ )

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Answer: (b)

$B_0 = \frac{E_0}{c}$ ; the frequency is not needed.
$B_0 = \frac{48}{3\times 10^{8}} = 1.6\times 10^{-7}\ \text{T}$ .
So the answer is (b).

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