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JEE Main 2022 (24 Jun, Shift 1) · Potentiometer

Potentiometer question from JEE Main 2022 (24 Jun, Shift 1)

Q48JEE Main 2022 · 24 JUN · SHIFT 1Easy

Potentiometer

In a potentiometer arrangement, a cell gives a balancing point at 75 cm length of wire. This cell is now replaced by another cell of unknown emf. If the ratio of the emf's of two cells respectively is 3: 2, the difference in the balancing length of the potentiometer wire in above two cases will be ___________ cm.

Numerical answer type. Work it out, then open the answer.

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Answer: 25

  1. E1E2=l1l2=32\frac{E_1}{E_2} = \frac{l_1}{l_2} = \frac{3}{2}.
  2. l2=75×23=50 cml_2 = 75 \times \frac{2}{3} = 50\ \text{cm}.
  3. Difference =75−50=25 cm= 75 - 50 = 25\ \text{cm}.
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