In a potentiometer experiment the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of 2 Ω, the balancing length becomes 120 cm. The internal resistance of the cell is (a) 0.5 Ω (b) 1 Ω (c) 2 Ω (d) 4 Ω

Answer: (c). r = R(l₀/l-1) r = 2((240)/(120)-1) = 2 Ω So the answer is (c) 2 Ω.

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Potentiometer

In a potentiometer experiment the balancing with a cell is at length $240\text{ cm}.$ On shunting the cell with a resistance of $2\ \Omega,$ the balancing length becomes $120\text{ cm}$ . The internal resistance of the cell is

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Answer: (c)

$r = R\left(\dfrac{l_0}{l}-1\right)$
$r = 2\left(\dfrac{240}{120}-1\right) = 2\ \Omega$
So the answer is (c) $2\ \Omega$ .

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