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NEET 2006 (AIPMT) · Law of Radioactive Decay

Law of Radioactive Decay question from NEET 2006 (AIPMT)

Q109NEET 2006 · AIPMTEasy

Law of Radioactive Decay

In a radioactive material the activity at time t1 is R1 and at a later time t2, it is R2. If the decay constant of the material is $\lambda$ , then

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Answer: (b)

$R_1 = R_0 e^{-\lambda t_1}$ and $R_2 = R_0 e^{-\lambda t_2}$ .
Dividing: $\frac{R_1}{R_2} = e^{-\lambda(t_1 - t_2)}$ .
So the answer is (b) $R_1 = R_2 e^{-\lambda(t_1 - t_2)}$ .

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