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JEE Main 2020 (5 Sep, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from JEE Main 2020 (5 Sep, Shift 1)

Q94JEE Main 2020 · 5 SEP · SHIFT 1Easy

Organ Pipes & Resonance Tube

In a resonance tube experiment when the tube is filled with water up to a height of 17.0 cm from bottom, it resonates with a given tuning fork. When the water level is raised the next resonance with the same tuning fork occurs at a height of 24.5 cm. If the velocity of sound in air is 330 m/s, the tuning fork frequency is:

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Answer: (a)

Two successive resonances differ in air-column length by $\frac{\lambda}{2}$ .
$\frac{\lambda}{2} = 24.5 - 17.0 = 7.5\text{ cm} \Rightarrow \lambda = 15\text{ cm} = 0.15\text{ m}$
$f = \frac{v}{\lambda} = \frac{330}{0.15} = 2200\text{ Hz}$
So the answer is (a) 2200 Hz.

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