In a series LCR circuit R = 300 Ω, L = 0.9 H, C = 2, ω = 1000 rad/s. The impedance of the circuit is (a) 500 Ω (b) 1300 Ω (c) 400 Ω (d) 900 Ω

Answer: (a). XL = ω L = 1000 × 0.9 = 900 Ω XC = (1)/(ω C) = 11000 × 2 × 10⁻⁶ = 500 Ω Z = √(300² + 400²) = 500 Ω So the answer is (a) 500 Ω.

In a series LCR circuit R = 300 Ω, L = 0.9 H, C = 2, ω = 1000 rad/s… | MHT CET 2019 (2 May, Shift 1)

Q56MHT CET 2019 · 2 MAY · SHIFT 1Easy

Series LCR Circuit

In a series $LCR$ circuit $R = 300\ \Omega,\ L = 0.9\text{ H},\ C = 2\ \mu\text{F},\ \omega = 1000\text{ rad/s}$ . The impedance of the circuit is

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Answer: (a)

$X_L = \omega L = 1000 \times 0.9 = 900\ \Omega$
$X_C = \frac{1}{\omega C} = \frac{1}{1000 \times 2 \times 10^{-6}} = 500\ \Omega$
$Z = \sqrt{300^2 + 400^2} = 500\ \Omega$
So the answer is (a) $500\ \Omega$ .