In a series LCR circuit, the inductance L = 20 mH, capacitor C = 2 μ F and resistance R = 100 ohm. The frequency at which resonance occurs is (a) ((10)²)/(2π) (b) ((10)³)/(3π) (c) ((10)⁴)/(4π) (d) 10/π

Answer: (c). ω₀ = (1)/(√(LC)) = 1√20×10⁻³ × 2×10⁻⁶ = 12×10⁻⁴ = 5000 rad/s f₀ = (5000)/(2π) = (10⁴)/(4π) Hz So the answer is (c) ((10)⁴)/(4π).

In a series LCR circuit, the inductance L = 20 mH, capacitor C = 2 μ… | MHT CET 2026 (12 May, Shift 1)

Q3MHT CET 2026 · 12 MAY · SHIFT 1Easy

Resonance, Bandwidth & Q Factor

In a series LCR circuit, the inductance $L = 20$ mH, capacitor $C = 2\ \mu$ F and resistance $R = 100$ ohm. The frequency at which resonance occurs is

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Answer: (c)

$\omega_0 = \dfrac{1}{\sqrt{LC}} = \dfrac{1}{\sqrt{20\times10^{-3} \times 2\times10^{-6}}} = \dfrac{1}{2\times10^{-4}} = 5000\text{ rad/s}$
$f_0 = \dfrac{5000}{2\pi} = \dfrac{10^4}{4\pi}\text{ Hz}$
So the answer is (c) $\dfrac{(10)^4}{4\pi}$ .

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Resonance, Bandwidth & Q Factor question from MHT CET 2026 (12 May, Shift 1)

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