In a series LCR circuit, the voltage across R is 100 V, R = 1 K Ω and C = 2 μ F. The angular frequency ω is 200 rad s ⁻¹. At resonance, the voltage across ' L ' is (a) 150 V (b) 200 V (c) 250 V (d) 300 V

Answer: (c). I = VR/R = (100)/(1000) = 0.1 A At resonance VL = VC = (I)/(ω C) = 0.1200×2×10⁻⁶ VL = 250 V So the answer is (c) 250 V.

In a series LCR circuit, the voltage across R is 100 V, R = 1 K Ω and… | MHT CET 2026 (20 Apr, Shift 1)

Q21MHT CET 2026 · 20 APR · SHIFT 1Medium

Resonance, Bandwidth & Q Factor

In a series LCR circuit, the voltage across R is $100$ V, $R = 1$ K $\Omega$ and $C = 2\ \mu$ F. The angular frequency $\omega$ is $200$ rad s ${}^{-1}$ . At resonance, the voltage across ' $L$ ' is

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Answer: (c)

$I = \frac{V_R}{R} = \frac{100}{1000} = 0.1$ A
At resonance $V_L = V_C = \frac{I}{\omega C} = \frac{0.1}{200\times2\times10^{-6}}$
$V_L = 250$ V
So the answer is (c) 250 V.

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