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MHT CET 2026 (13 Apr, Shift 2) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from MHT CET 2026 (13 Apr, Shift 2)

Q14MHT CET 2026 · 13 APR · SHIFT 2Medium

Power, Power Factor & Wattless Current

In a series LR circuit with $X_L = R$ . Power factor is $P_1$ . If a capacitor of capacitance $C$ with $X_c = X_L$ is added to the circuit the power factor becomes $P_2$ . The ratio of $P_1$ to $P_2$ will be:

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Answer: (b)

LR with $X_L = R$ : $Z = \sqrt{2}R$ , $P_1 = \frac{1}{\sqrt{2}}$ .
Adding C with $X_C = X_L$ gives resonance: $Z = R$ , $P_2 = 1$ .
$P_1 : P_2 = \frac{1}{\sqrt{2}} : 1 = 1 : \sqrt{2}$ .
So the answer is (b) $1:\sqrt{2}$ .

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