In a single slit diffraction experiment, for a wavelength of light ' λ ', half-angular width of the principal maxima is ' θ '. Also for wavelength of light pλ, the half angular width of the principal maxima is qθ. The ratio of the half-angular widths of the first secondary maxima in the first case to second case will be (a) p: 1 (b) q: 1 (c) p: q (d) q: p

Answer: (b). Half angular width of central maximum = (λ)/(a); the width of each secondary maximum is also set by (λ)/(a). So the secondary-maximum widths are in the same ratio as the principal half widths. Case 1: case 2 = θ: qθ = 1: q

In a single slit diffraction experiment, for a wavelength of light '… | MHT CET 2024 (16 May, Shift 2)

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Diffraction at a Single Slit

In a single slit diffraction experiment, for a wavelength of light ' $\lambda$ ', half-angular width of the principal maxima is ' $\theta$ '. Also for wavelength of light $p\lambda$ , the half angular width of the principal maxima is $q\theta$ . The ratio of the half-angular widths of the first secondary maxima in the first case to second case will be

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Answer: (b)

Half angular width of central maximum $= \dfrac{\lambda}{a}$ ; the width of each secondary maximum is also set by $\dfrac{\lambda}{a}$ .
So the secondary-maximum widths are in the same ratio as the principal half widths.
Case 1 : case 2 $= \theta : q\theta = 1 : q$

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