In a single slit diffraction experiment, slit of width ' a ' is… | MHT CET 2025 (25 Apr, Shift 2)

Q23MHT CET 2025 · 25 APR · SHIFT 2Medium

Diffraction at a Single Slit

In a single slit diffraction experiment, slit of width ' $a$ ' is illuminated by light of wavelength ' $\lambda$ ' and the width of the central maxima in diffraction pattern is measured as ' $y$ '. When half of the slit is covered and illuminated by light of wavelength (1.5) $\lambda$ , the width of the central maximum in diffraction pattern becomes

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Answer: (c)

Central width $y = \dfrac{2\lambda D}{a} \propto \dfrac{\lambda}{a}$
New: $\lambda' = 1.5\lambda$ , $a' = \dfrac{a}{2}$ , so $\dfrac{y'}{y} = 1.5 \times 2 = 3$
So the answer is (c) $3y$ .

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