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MHT CET 2021 (20 Sep, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2021 (20 Sep, Shift 2)

Q61MHT CET 2021 · 20 SEP · SHIFT 2Medium

Diffraction at a Single Slit

In a single slit diffraction pattern, the distance between the first minimum on the left and the first minimum on the right is 5 mm5\text{ mm}. The screen on which the diffraction pattern is obtained is at a distance of 80 cm80\text{ cm} from the slit. The wavelength used is 6000 A˚\text{\AA}. The width of the silt is

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Answer: (c)

  1. Distance between first minima on either side: W=2DλaW = \dfrac{2D\lambda}{a}.
  2. a=2DλW=2×0.8×6×10−75×10−3=1.92×10−4 ma = \dfrac{2D\lambda}{W} = \dfrac{2 \times 0.8 \times 6\times10^{-7}}{5\times10^{-3}} = 1.92\times10^{-4}\text{ m}
  3. So the answer is (c) 0.192 mm0.192\text{ mm}.
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