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MHT CET 2025 (22 Apr, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2025 (22 Apr, Shift 2)

Q22MHT CET 2025 · 22 APR · SHIFT 2Medium

Diffraction at a Single Slit

In a single slit diffraction pattern, the distance between the plane of the slit and screen is 1.3 m. The width of the slit is 0.65 mm and the second maximum is formed at the distance of 2.6 mm from the centre of the screen. The wavelength of light used is

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Answer: (c)

  1. Second secondary maximum: y=5λD2a⇒λ=2ay5Dy = \dfrac{5\lambda D}{2a} \Rightarrow \lambda = \dfrac{2ay}{5D}
  2. λ=2×0.65×10−3×2.6×10−35×1.3=5.2×10−7\lambda = \dfrac{2 \times 0.65 \times 10^{-3} \times 2.6 \times 10^{-3}}{5 \times 1.3} = 5.2 \times 10^{-7} m
  3. So the answer is (c) 52005200 Å.
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